Enter any 3 values of the initial and final temperatures and pressures of an ideal gas to calculate the missing value using Gay-Lussac’s Law.
Gay-Lussac’s Law Formula
The following formula describes the relations between temperature and pressure in an ideal gas.
P1 / T1 = P2 / T2
- Where P1 is the initial pressure
- T1 is the initial temperature
- P2 is the final pressure
- T2 is the final tempature
Guy-Lussac’s law states that the pressure and temperature of an ideal gas are directly proportional.
Guy-Lussac’s Law Example
Let’s look at an example of how to calculate one of the missing values using Gay-Lussac’s Law. Let’s assume we know the initial temperature (5K), final pressure (5Pa), and final temperature (10K). To calculate the initial pressure we must rearrange the equation above to solve for P1. So, P1 = (P2/T2) * T1 = 5/5 * 10 = 10 Pa.
This law states that in an ideal gas the temperature and pressure our directly proportional. If the pressure goes up by 2 times, the temperature will go up by 2 times.