Calculate beam size for a simple span: enter span and load, pick wood, glulam, LVL or steel, and get the required section modulus or rectangular depth.

Use the applicable uniform load, including distributed self-weight when known. This case does not add a separate point load.

Use the applicable adjusted allowable stress, not yield or ultimate strength. No generic material property is assumed.

Optional settings


Related Calculators

Calculator Functions

FunctionWhat it doesWhat it requires
Section modulus ยท uniform loadFinds the section modulus a simple-span beam needs to carry a load spread evenly along its full lengthRequires the span between supports, the uniform line load and a beam material or allowable bending stress
Section modulus ยท center loadFinds the section modulus a simple-span beam needs to carry one point load at mid-spanRequires the span between supports, the point load and a beam material or allowable bending stress
Depth ยท uniform loadFinds the minimum depth of a rectangular beam of known width under a full-span uniform loadRequires the span, the uniform line load, a beam material or allowable bending stress, and the actual beam width
Depth ยท center loadFinds the minimum depth of a rectangular beam of known width under one point load at mid-spanRequires the span, the point load, a beam material or allowable bending stress, and the actual beam width

Every function covers a single span resting on two supports. The Beam material list fills in a bending stress and stiffness for Douglas fir No. 2, glulam, LVL and two steel grades, and Custom Fb and E accepts any other values. Setting the Deflection requirement to Also check deflection adds a stiffness check against a limit such as L/360. Span can be entered in ft, in, m or mm, and loads in lb/ft, lb/in, kN/m, N/m, lb, kN or N.

Beam Size Formulas

S = M รท Fb
SRequired section modulus (inยณ)
MMaximum bending moment (lb-in, which is lb-ft ร— 12)
FbAdjusted allowable bending stress (psi), not yield or ultimate strength

The beam passes the bending check when its section modulus is at least S. The four functions differ only in how the moment is found and whether S is turned into a depth.

Section modulus ยท uniform load

M = w ร— Lยฒ รท 8 [1]

w is the load per unit length over the whole span and L is the span. The largest moment is at mid-span. A 10 ft span carrying 1,000 lb/ft has M = 1,000 ร— 10ยฒ รท 8 = 12,500 lb-ft, and at Fb = 1,200 psi it needs S = 12,500 ร— 12 รท 1,200 = 125 inยณ. The uniform load should include the beam’s own weight when it is known.

Section modulus ยท center load

M = P ร— L รท 4 [1]

P is a single load at the middle of the span. A 5,000 lb load on a 10 ft span gives the same 12,500 lb-ft as the uniform example, because that uniform load totals 10,000 lb and a center load bends a beam twice as hard as the same weight spread out. This function models the point load alone and does not add the beam’s own weight.

Depth ยท uniform load

d = โˆš(6 ร— S รท b)

A solid rectangle of width b and depth d has S = b ร— dยฒ รท 6, and this is that relation solved for d. With S = 125 inยณ and an actual width of 3.5 in, d = โˆš(6 ร— 125 รท 3.5) = 14.64 in. The width is the actual dimension, not the nominal lumber size: a nominal 4 in member is 3.5 in wide. The result is a minimum, to be rounded up to a section that is actually sold.

Depth ยท center load

The depth comes from the same rectangle relation, with S taken from the center-load moment P ร— L รท 4.

Deflection check

I = 5 ร— w ร— Lยณ ร— r รท (384 ร— E)
I = P ร— Lยฒ ร— r รท (48 ร— E)

With Also check deflection selected, the calculator also finds the second moment of area I that keeps mid-span deflection within L รท r, where r is the limit denominator (360 for L/360) and E is the modulus of elasticity. The first line is for a uniform load and the second for a center load. They come from the maximum deflections 5wLโด รท (384EI) and PLยณ รท (48EI) [1], set equal to L รท r. The depth functions then use I = b ร— dยณ รท 12 to get a second depth, d = โˆ›(12 ร— I รท b), and report the larger of the two along with which check governs.

For the 5,000 lb center load on 10 ft with E = 1,600,000 psi and L/360, I = 337.5 inโด and the deflection depth at 3.5 in wide is 10.50 in, so the 14.64 in bending depth governs.

Material values in the Beam material list

Beam materialFb (psi)E (psi)
Douglas fir-larch No. 29001,600,000
Glulam 24F-V42,4001,800,000
LVL 2.0E2,6002,000,000
Steel A992 (Fy 50 ksi)33,00029,000,000
Steel A36 (Fy 36 ksi)24,00029,000,000

The wood figures are reference values before any adjustment. Published lumber stresses are adjusted for size, moisture, duration of load and other conditions before they are used in design [2], so the stress that applies to a given beam can be higher or lower than the number in the list. The steel figures are 0.66 ร— Fy, an allowable-stress value for compact sections braced against sideways buckling. A steel beam is chosen by finding a shape whose listed section modulus is at least S, so the two section modulus functions are the ones to use for steel I-beams, and the depth functions apply only to solid rectangles such as sawn lumber, glulam and LVL.

How to Calculate Beam Size

Beam size follows from four numbers: the span, the load, the allowable bending stress of the material and, for a rectangular beam, its width. Find the maximum moment from the span and load (w ร— Lยฒ รท 8 for a uniform load, P ร— L รท 4 for a center load), convert it to lb-in, and divide by the allowable bending stress to get the required section modulus. For a rectangular beam, d = โˆš(6 ร— S รท b) turns that into a depth. If a deflection limit applies, work out the required I as well and keep the larger depth. A beam sized this way has passed bending and deflection only, which is the starting point for a design and not the end of it.

Limits of This Estimate

  • The result covers elastic bending and, when selected, deflection. It does not check shear, bearing at the supports, lateral stability, connections, combined loads, long-term creep or vibration. A qualified engineer should verify the final section and the load combinations.
  • Only a single span on two simple supports is modeled, with either a full-span uniform load or one load at mid-span. Cantilevers, continuous beams, partial loads and off-center loads have different moments.
  • The material list holds typical values, and a result that uses it is labeled an estimate. The grade stamp, the manufacturer’s literature and the governing code give the values for a specific beam. These estimates are based on the best available data and estimations.
  • The same load is used for bending and for deflection. Building codes can require separate total-load and live-load deflection checks.

Sources

  1. American Wood Council, Design Aid No. 6, Beam Design Formulas with Shear and Moment Diagrams, Figures 1 and 7: maximum moment and deflection of a simple beam under a uniform load and under a load at the center
  2. USDA Forest Products Laboratory, Wood Handbook (FPL-GTR-282), Chapter 7: how lumber properties are adjusted for size, moisture and duration of load to give design stresses