Estimate motor power in kW from operating frequency, rated power, and rated Hz for pump, fan, or conveyor loads with torque scaling.
Hz To Kw Formula
The following formula estimates mechanical shaft power (kW) from electrical frequency (Hz), pole count, and shaft torque for a synchronous motor/generator operating at synchronous speed (i.e., neglecting slip and losses).
P_{kW}=\frac{4\pi f\,\tau}{P_c\cdot 1000}Variables:
- P is the power output (kW)
- τ is the shaft torque (N·m)
- f is the frequency (Hz)
- P_c is the pole count
| Frequency (Hz) | Power (kW) |
|---|---|
| 5 | 0.157 |
| 10 | 0.314 |
| 15 | 0.471 |
| 20 | 0.628 |
| 30 | 0.942 |
| 40 | 1.257 |
| 50 | 1.571 |
| 60 | 1.885 |
| 75 | 2.356 |
| 90 | 2.827 |
| 100 | 3.142 |
| 120 | 3.770 |
| 150 | 4.712 |
| 180 | 5.655 |
| 200 | 6.283 |
| 240 | 7.540 |
| 300 | 9.425 |
| 360 | 11.310 |
| 400 | 12.566 |
| 500 | 15.708 |
| * Rounded to 3 decimals. Formula: P(kW) = (4π f τ) / (Pc × 1000). Assumes torque τ = 10 N·m and pole count Pc = 4. 1 kW = 1000 W. | |
What is Hz To Kw?
Hz (hertz) is a unit of frequency (cycles per second), while kW (kilowatt) is a unit of power. There is no universal “Hz to kW” conversion because power depends on the system. In rotating AC machines, frequency and pole count determine synchronous speed (for example, 60 Hz and 4 poles corresponds to 1800 rpm), and with a known shaft torque you can estimate mechanical power using P = τ·ω. (If you need electrical real power from voltage/current, frequency is not a multiplicative factor; for example, three‑phase real power is P(kW) = √3 · V · I · PF / 1000.)
How to Calculate Hz To Kw?
The following steps outline how to estimate mechanical kW from frequency using the given formula:
- Determine the frequency (f) in hertz (Hz).
- Determine the pole count (Pc) of the machine (2, 4, 6, …).
- Determine the shaft torque (τ) in newton‑meters (N·m).
- Calculate the synchronous angular speed: ω = 4πf / Pc (rad/s).
- Calculate mechanical power in watts: P(W) = τ · ω.
- Convert watts to kilowatts: P(kW) = P(W) / 1000, which gives P(kW) = (4π f τ) / (Pc × 1000).
Example Problem:
Use the following variables as an example problem to test your knowledge:
frequency (f) = 60 Hz
pole count (Pc) = 4
shaft torque (τ) = 10 N·m
power (P) = (4π · 60 · 10) / (4 · 1000) = 1.88496 kW
