Calculate hydraulic horsepower from pressure difference and US gallons per minute, or solve for PSI, flow, shaft power and pump efficiency. A separate boost mode provides only an idealized engine pressure-ratio comparison.

Hydraulic power uses pressure difference and US gallons per minute. The boost mode is an idealized pressure-ratio estimate, not an engine rating or tuning recommendation.

Optional settings

When supplied, includes the shaft power needed at this operating point.

PSI ↔ HP Conversion Table (Flow = 10 GPM)
PSI to HP (at 10 GPM) HP to PSI (at 10 GPM)
500 psi = 2.917 hp1 hp = 171.4 psi
750 psi = 4.376 hp2 hp = 342.8 psi
1,000 psi = 5.834 hp3 hp = 514.2 psi
1,250 psi = 7.293 hp5 hp = 857 psi
1,500 psi = 8.751 hp7.5 hp = 1,285.5 psi
1,750 psi = 10.210 hp10 hp = 1,714 psi
2,000 psi = 11.669 hp15 hp = 2,571 psi
2,500 psi = 14.586 hp20 hp = 3,428 psi
3,000 psi = 17.503 hp25 hp = 4,285 psi
3,500 psi = 20.420 hp30 hp = 5,142 psi
Formulas: HP = (PSI x GPM) / 1714 and PSI = (HP x 1714) / GPM.
PSI ↔ HP Conversion Table (Flow = 20 GPM)
PSI to HP (at 20 GPM) HP to PSI (at 20 GPM)
500 psi = 5.834 hp2 hp = 171.4 psi
750 psi = 8.751 hp5 hp = 428.5 psi
1,000 psi = 11.669 hp7.5 hp = 642.75 psi
1,250 psi = 14.586 hp10 hp = 857 psi
1,500 psi = 17.503 hp15 hp = 1,285.5 psi
1,750 psi = 20.420 hp20 hp = 1,714 psi
2,000 psi = 23.337 hp25 hp = 2,142.5 psi
2,500 psi = 29.172 hp30 hp = 2,571 psi
3,000 psi = 35.006 hp40 hp = 3,428 psi
3,500 psi = 40.840 hp50 hp = 4,285 psi
Formulas: HP = (PSI x GPM) / 1714 and PSI = (HP x 1714) / GPM.

psi to Horsepower Formula

hp = (psi × gpm) / 1714

hp = hydraulic horsepower | psi = pressure in pounds per square inch | gpm = flow rate in US gallons per minute

The constant 1714 comes from unit conversions: 1 HP = 33,000 ft·lb/min; 1 US gallon = 231 cubic inches; 1 PSI = 144 lb/ft². The exact unit ratio is 33,000 × 12 / 231 = 1,714.285714…. This calculator and the tables use the conventional rounded factor 1714; results are approximate.

Illustrative Hydraulic HP Calculations

Illustrative Hydraulic HP from Assumed Inputs
Example label Assumed PSI Assumed US GPM Hydraulic HP Range
Log splitter2,500–3,0002–52.9–8.8 hp
Skid steer loader3,000–3,50015–3026–61 hp
Mini excavator3,000–4,00015–2526–58 hp
Agricultural tractor2,000–3,00010–2012–35 hp
Industrial power unit1,000–3,0005–503–88 hp
High-pressure press5,000–10,0002–106–58 hp
Crane / lift3,000–4,00020–5035–117 hp
Illustrative assumed inputs only, not equipment specifications or operating limits. HP = (PSI x US GPM) / 1714. Use the manufacturer’s actual pressure, flow and overall efficiency at the operating point.

Hydraulic HP vs. Required Motor HP

The formula gives theoretical hydraulic horsepower at 100% efficiency. Real pumps have mechanical losses, so the motor or engine must supply more than the hydraulic HP output. Divide hydraulic HP by pump efficiency to find required input power.

Illustrative Efficiencies (Shaft HP per 10 Hydraulic HP)
Pump Type Assumed Efficiency Motor HP per 10 HHP
Gear pump80–85%11.8–12.5 HP
Vane pump82–87%11.5–12.2 HP
Axial piston pump87–95%10.5–11.5 HP
Shaft HP = hydraulic HP / efficiency as a fraction. These assumed efficiencies are examples, not ratings by pump type. Consult actual operating data and include applicable starting, duty and service requirements.

What is PSI?

PSI (pounds per square inch) measures hydraulic fluid pressure. It represents the force per unit area the pump exerts on the fluid. Most industrial hydraulic systems operate at 1,000 to 5,000 PSI. High-pressure circuits for presses or specialized equipment can exceed 10,000 PSI. Higher PSI produces more force from a given cylinder bore but increases heat generation and component wear.

What is Hydraulic Horsepower?

Hydraulic horsepower (HHP) is the power carried by pressurized fluid. It is distinct from shaft or motor horsepower: HHP is the theoretical power delivered to the hydraulic actuator, while shaft HP is what the engine or electric motor must supply to achieve it. For a real pump with losses, shaft input power exceeds its hydraulic output; at ideal 100% efficiency they are equal. A pump with 90% efficiency delivering 10 HHP requires 11.1 shaft HP from the motor.

Worked Example

Given: Pressure = 150 psi, Flow rate = 50 gpm

hp = (150 × 50) / 1714 = 7500 / 1714 = 4.376 hp

At 85% overall pump efficiency, shaft input power is approximately 4.376 / 0.85 = 5.15 HP. Final motor selection also requires actual starting, duty, service and manufacturer requirements.