Calculate theoretical velocity from height or find the height needed for a given velocity using gravity and metric or imperial units.

Ideal fall from rest with constant standard gravity, 9.80665 m/s², and no air resistance. Returns speed magnitude.

Theoretical Velocity Formula

The calculator estimates ideal free-fall speed from a vertical drop height, or reverses that calculation. It assumes an object starts from rest, constant standard gravity g = 9.80665 m/s², and no air resistance.

v = √(2gh)
h = (v²) / (2g)
  • v = nonnegative theoretical speed
  • h = nonnegative vertical drop height
  • g = standard gravity, 9.80665 m/s²

Choose Theoretical speed from height or Drop height from speed, enter the known quantity and select a result unit. Changing an input unit converts its existing value; changing the result unit takes effect on the next Calculate.

Velocity Unit Conversion Factors

The calculator supports meters per second, kilometers per hour, miles per hour, and feet per second.

Unit Convert to m/s Convert from m/s
m/s multiply by 1 multiply by 1
km/h divide by 3.6 multiply by 3.6
mph multiply by 0.44704 divide by 0.44704
ft/s multiply by 0.3048 divide by 0.3048

Height and Theoretical Velocity Relationship

Known Value Formula to Use Meaning
Drop height v = √(2gh) Finds ideal speed after a vertical fall from rest.
Theoretical speed h = v² ÷ (2g) Finds the ideal drop height needed for a speed.

Example Problems

Example 1: Find speed from drop height

Suppose the vertical drop height is 10 m.

v = √(2 × 9.80665 × 10)
v ≈ 14.00474919 m / s

The theoretical speed is approximately 14.00474919 m/s.

Example 2: Find drop height from speed

Suppose the theoretical speed is 10 m/s.

h = 10² / (2 × 9.80665)
h ≈ 5.09858106 m

The ideal drop height is approximately 5.09858106 m.

FAQ

What does theoretical velocity mean here?

Here it means the speed magnitude predicted by ideal free fall from rest. Direction is not inferred from a signed velocity input.

Does the estimate include air resistance?

No. Drag, buoyancy and altitude-dependent gravity are omitted. This constant-gravity model is unsuitable for long drops or terminal-speed predictions.

Can I enter zero height or zero speed?

Yes. Zero drop height corresponds to zero speed for an object starting from rest. Negative height and speed are outside this magnitude-based model.