Calculate a basis for the image of a linear transformation from its matrix, identifying pivot column vectors and the rank or dimension of Im(T).
Customize This Calculator
Build your own version. Describe what you want changed, added, or compared.
Basis Of Image Formula
The image (also called the range) of a linear transformation T is the set of all outputs T(v). A basis of the image is any linearly independent set of vectors that spans this image.
Variables:
- Im(T) is the image (range) of the transformation T
- V is the domain vector space
- T(v) is the output of the linear transformation applied to the input vector v
- A is a matrix representation of T (with respect to chosen bases); the image is the column space Col(A)
To find a basis of the image, apply T to a spanning set (typically a basis) of V to get vectors in the codomain, then keep a linearly independent subset that still spans the same set of outputs. If T is given by a matrix A, a standard method is to row-reduce A to find the pivot columns; the corresponding columns of the original matrix form a basis for the image (the column space).
What is the Basis of Image?
A basis of an image, in the context of linear algebra, refers to a set of vectors that spans the image of a linear transformation or a matrix. These vectors are linearly independent, meaning they cannot be expressed as a linear combination of each other. The basis of an image provides a way to describe every vector in the image space in terms of a linear combination of the basis vectors.
How to Calculate Basis Of Image?
The following steps outline a common way to calculate a basis of the image.
- Identify the linear transformation T:V\to W (or its matrix A with respect to chosen bases).
- Choose a basis {v1,…,vn} of the domain V.
- Compute the images T(v1),…,T(vn), which are vectors in the codomain W.
- Form a matrix whose columns are these vectors (equivalently, if you already have the matrix A, its columns are T(e1),…,T(en) in standard coordinates).
- Row-reduce to find which columns are pivot columns, then take the corresponding columns of the original matrix as a basis for Im(T). The number of basis vectors is the rank (dimension of the image).
Example Problem:
Use the following variables as an example problem to test your knowledge:
Let {v1, v2, v3, v4} be a basis of a vector space V.
Define the linear transformation T(v)=2v (over the real numbers, or any field where 2 ≠ 0).
Then Im(T)=V, and one basis of the image is {T(v1),T(v2),T(v3),T(v4)} = {2v1,2v2,2v3,2v4} (which is also a basis of V).
