Enter the lvl length (ft), the lvl width (ft), and the lvl thickness (in) into the Laminated Veneer Lumber Weight Calculator. The calculator will evaluate the Laminated Veneer Lumber Weight.
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Understanding LVL Weight
The LVL weight calculator estimates the weight of a laminated veneer lumber member from its volume and an assumed material density. In practical terms, this helps with delivery planning, manual handling, staging, hoisting, storage layout, and checking whether a member is realistic to move with a crew, cart, forklift, or lift equipment.
W = V \times \rho
V = L \times b \times \frac{t}{12}W = L \times b \times \frac{t}{12} \times 41\rho \approx 41\ \mathrm{lb/ft^3}In these formulas, L is the member length in feet, b is the member width/depth in feet, t is thickness in inches, and W is the estimated weight in pounds. The fraction t / 12 converts inches to feet so the volume stays consistent in cubic feet.
Variable Guide
| Variable | Meaning | Typical Unit | Important Note |
|---|---|---|---|
| L | LVL length | ft | Use the full installed or handled length. |
| b | LVL width/depth | ft | If your size is listed in inches, convert to feet or use the calculator’s unit selector. |
| t | LVL thickness | in | Use actual thickness, not a rounded nominal description. |
| W | Estimated total weight | lb or kg | The calculator can also reverse-solve a missing value when three values are known. |
Shortcut for Weight Per Linear Foot
For beam handling, the most useful number is often weight per foot. If both cross-sectional dimensions are known in inches, you can estimate pounds per linear foot directly:
w_f = \frac{b_i \times t_i \times 41}{144}Here, bi and ti are the actual cross-sectional dimensions in inches, and wf is the weight per linear foot. Once you know pounds per foot, multiply by total length to get total weight.
W = w_f \times L
Example
A 16 ft LVL with actual cross-sectional dimensions of 11.875 in by 1.75 in has an estimated weight per foot of about 5.92 lb/ft, which gives a total estimated weight of about 94.7 lb.
w_f = \frac{11.875 \times 1.75 \times 41}{144} \approx 5.92\ \mathrm{lb/ft}W = 5.92 \times 16 \approx 94.7\ \mathrm{lb}Approximate LVL Weights Per Linear Foot
The table below uses common actual LVL cross-sections and the same 41 lb/ft3 assumption used by the calculator. These numbers are estimates, but they are very useful for quick planning.
| Actual Thickness | Actual Depth | Approx. Weight per Foot |
|---|---|---|
| 1.75 in | 9.25 in | 4.61 lb/ft |
| 1.75 in | 11.875 in | 5.92 lb/ft |
| 1.75 in | 14 in | 6.98 lb/ft |
| 1.75 in | 16 in | 7.97 lb/ft |
| 1.75 in | 18 in | 8.97 lb/ft |
| 3.5 in | 11.875 in | 11.83 lb/ft |
| 3.5 in | 14 in | 13.95 lb/ft |
| 3.5 in | 16 in | 15.94 lb/ft |
What Changes the Actual Weight?
- Moisture content: wetter members weigh more than drier members.
- Manufacturer differences: veneer species, resin content, and product line can shift density.
- Treatment or coatings: fire treatment, preservatives, or finishes can add mass.
- Actual vs nominal dimensions: always measure or confirm the real section size before estimating.
- Field cuts and notches: trimming, holes, and cutbacks reduce total weight.
Practical Tips for Using the Calculator
- Enter actual dimensions whenever possible.
- Keep unit selections consistent if you switch between feet, inches, meters, or centimeters.
- Use the result as an estimate for planning, not as a substitute for product-specific handling data.
- For crane picks, rigging plans, or transport-critical work, verify the exact member weight from project documents or supplier data.
Common Questions
Does a longer LVL always weigh more? Yes. If the cross-section stays the same, total weight increases in direct proportion to length.
Why is thickness often entered in inches? Because structural wood products are commonly specified by actual thickness in inches, even when overall length is entered in feet.
Can this calculator solve for a missing value? Yes. If you know any three of the four variables, the missing value can be estimated.
Should I use nominal beam sizes? No. Use actual dimensions for the best estimate, since even small dimension differences can noticeably change the final weight.
