Enter ion concentrations (for a 1:1 salt) or enter Ksp with the dissolution stoichiometry (molar solubility tab) to calculate the solubility product constant (Ksp). Ksp describes the equilibrium between a sparingly soluble solid and its dissolved ions at a specified temperature.
Solubility Constant Formula
The solubility product constant is written from the balanced dissolution reaction. For a salt that dissolves as:
A_aB_b(s)\rightleftharpoons aA + bB
The Ksp expression is:
K_{sp} = [A]^a[B]^bFor a 1:1 salt AB(s) ⇌ A + B, this becomes Ksp = [A][B]. In pure water (no added common ions) the molar solubility is S and [A]=[B]=S, so Ksp = S² (ignoring activity effects).
Variables:
- Ksp is the solubility product constant (defined for a specific dissolution reaction and temperature).
- [A] and [B] are the equilibrium molar concentrations of the dissolved ions (mol/L).
- a and b are the stoichiometric coefficients from the balanced dissolution equation (and also the exponents in the Ksp expression).
- S is the molar solubility (mol/L) of the solid in pure water (when applicable).
What is a Solubility Constant?
The solubility constant, also known as the solubility product constant (Ksp), describes the equilibrium between a sparingly soluble ionic solid and its dissolved ions. It is a constant for a given substance at a specific temperature and is used to estimate solubility and predict whether a precipitate will form (via comparison of the ion product Q to Ksp).
How to Calculate Solubility Constant?
The following steps outline how to calculate the Solubility Product Constant (Ksp).
- Write the balanced dissolution reaction for the solid (for example, AaBb(s) ⇌ aA + bB).
- Write the Ksp expression using the stoichiometric coefficients as exponents: Ksp = [A]a[B]b.
- Determine the equilibrium ion concentrations. In pure water, these can often be written in terms of molar solubility S (e.g., [A]=aS and [B]=bS).
- Substitute the equilibrium concentrations into the Ksp expression and solve for Ksp (or solve for S if Ksp is known).
Example Problem :
Silver chloride dissolves as AgCl(s) ⇌ Ag+ + Cl−. If its molar solubility in pure water is S = 1.33Ă—10−5 mol/L, then:
Ksp = S² = (1.33Ă—10−5)² ≈ 1.77Ă—10−10
