Estimate product heat load from mass, temperatures, product-specific properties and cooling time, or batch throughput from a known rate and time.

Estimate average product heat load using your product-specific thermal data. This is not a complete equipment sizing or freezing-time model.

Use product temperature, not freezer air temperature.

Use product temperature, not freezer air temperature.

Use product-specific data. This simplified model concentrates the phase change at one temperature.

Use a validated average for this product and temperature interval.

Use a validated average for this product and temperature interval.

Product-specific phase-change energy over the interval. Food does not all freeze at a single temperature.

Available time for removing this load or processing at the stated rate. This calculator does not predict freezing time.

Additional allowance

Blank means 0%. An allowance does not validate or replace a full room, fan, packaging and infiltration load calculation.


Related Calculators

Blast Freezer Capacity Formula

Choose product load through freezing, cooling unfrozen product, cooling already frozen product, or batch mass from a known rate.

Product load through freezing estimates average product heat load using constant specific heats and a single phase-change temperature. Start strictly above and finish strictly below that point. This does not predict achievable freezing time or total equipment capacity.

Qโ‚œotal = m ร— Cpโ‚bove ร— (Ti - Tfโ‚šoint) + m ร— L + m ร— Cpbelow ร— (Tfโ‚šoint - Tf) Capacity (kW) = Qโ‚œotal / (t ร— 3600) ร— (1 + SF / 100)
  • m = product mass per batch (kg)
  • Cp_above = specific heat above freezing (kJ/kgยฐC)
  • Cp_below = specific heat below freezing (kJ/kgยฐC)
  • L = latent heat of freezing (kJ/kg)
  • Ti = initial product temperature (ยฐC)
  • Tf = final product temperature (ยฐC)
  • Tf_point = product freezing point (ยฐC)
  • t = effective available cooling time (hours)
  • SF = safety factor or allowance (%)

Batch capacity mode multiplies a known freezing rate by a freezing time to give total throughput per cycle.

Capacity = Rate ร— Time
  • Rate = freezing rate (kg/hour or lb/hour)
  • Time = freezing time (hours)

Through-freezing mode adds three heat loads: sensible heat to cool the product to its freezing point, latent heat to convert water to ice, and sensible heat to bring the frozen product to the target. The result is divided by time and multiplied by the allowance to give kW. Cooling-only tasks omit latent heat and use the appropriate specific heat over the full entered interval; choose them only when no phase change occurs. Batch mode gives mass output at a verified constant rate.

Illustrative Product Properties and Allowances

The legacy values below are illustrative assumptions, not validated data for every food in each category. They are no longer calculator presets. Enter product-specific properties for the actual temperature interval; measured enthalpy data are preferable.

Product Cp above (kJ/kgยฐC) Cp below (kJ/kgยฐC) Latent (kJ/kg) Freeze point (ยฐC)
Meat / poultry3.21.7250-1.5
Fish / seafood3.61.9270-1.0
Vegetables / fruit3.81.9300-1.0
Bakery / prepared2.71.4180-2.0
Water / ice4.182.13340

The output is product heat load plus your entered allowance (blank means zero). An allowance does not establish that omitted loads are covered. The percentages below illustrate margin sizes, not recommendations or guarantees for the listed conditions.

Allowance Illustrative percentage Loads to assess separately
Light10%Well-insulated room, infrequent door use
Standard15 to 20%Fans, lights, packaging, normal door cycles
Heavy25 to 30%Frequent loading, warm ambient, racks and trolleys

Worked Example

For an arithmetic example, assume 500 kg of product from +5ยฐC to โˆ’18ยฐC in 8 available cooling hours, using the tableโ€™s illustrative meat properties and a 15% allowance. These assumptions must be validated for a real product.

Sensible heat above freezing: 500 ร— 3.2 ร— (5 โˆ’ (โˆ’1.5)) = 10,400 kJ

Latent heat: 500 ร— 250 = 125,000 kJ

Sensible heat below freezing: 500 ร— 1.7 ร— (โˆ’1.5 โˆ’ (โˆ’18)) = 14,025 kJ

Total heat removed: 149,425 kJ

Base capacity: 149,425 รท (8 ร— 3600) = 5.19 kW

With 15% allowance: 5.19 ร— 1.15 = 5.97 kW average product load with allowance.

FAQ

Why does the calculator split heat load into three parts?
Freezing is not a linear process. Removing sensible heat above the freezing point, removing latent heat to form ice crystals, and cooling the frozen mass each take different amounts of energy per degree. Latent heat is by far the largest of the three for most foods.

Does the result include room and infiltration loads?
No. The sizing output covers product load plus the safety factor you enter. Door openings, wall transmission, fans, lights, and people loads should be added separately for final equipment selection.

When should I use batch capacity mode instead?
Use batch mode when the manufacturer has given you a freezing rate in kg/hour or lb/hour and you want to know the total mass per cycle. Use a product-load task when you have suitable thermal-property data, mass, temperatures and available cooling time. A complete refrigeration load and heat-transfer assessment is still needed.

What freezing time should I use?
Use a validated process time for the product thickness, packaging, airflow, temperatures and equipment. Account for loading, unloading and defrost consistently. This calculator does not establish a safe freezing time or guarantee the target core temperature.