HGV = pi*T * (Ro – Ri) ^2

• T is the thickness (in)
• Ro is the outer radius (in)
• Ri is the inner radius (in)

Example Problem #1

1. First, determine the thickness (in).
1. The thickness (in) is given as .25.
2. Next, determine the outer radius (in).
1. The outer radius (in) is calculated as: 4.
3. Next, determine the inner radius (in).
1. The inner radius (in) is found to be: 3.

HGV = pi*T * (Ro – Ri) ^2

Inserting the values from above yields:

HGV = pi*.25*(4 – 3) ^2 = .785 (in^3)

Example Problem #2

The variables needed for this problem are provided below:

thickness (in) = .6