Enter the voltage, frequency, and component values (inductance, capacitance, or resistance) into the calculator to determine the current in an AC circuit.

Hz to Amps Calculator

Use voltage plus watts, VA, or HP to estimate amps. Frequency helps identify the AC system, but frequency alone does not determine current.

Device Amps
Hz ↔ RPM
Advanced AC
120 V
208 V
220 V
230 V
240 V
V
50 Hz
60 Hz
Hz
W
0-1
0-1
For resistive loads, power factor is usually 1. For motors, power factor and efficiency are estimates unless you know the nameplate values.
Hz
RPM
Enter frequency or RPM, plus pole count. The result uses synchronous motor speed.
Inductor
Capacitor
RLC
Enter any 3 values to solve the missing one.
Enter any 3 values to solve the missing one.
Enter voltage and frequency, then any of R, L, and C. Blank L or C means that part is not used.
Hz ↔ Amps Conversion Table (Inductor, V = 120 V RMS, L = 10 mH)
Hz to Amps Amps to Hz
50 Hz = 38.197 A0.1 A = 19099 Hz
60 Hz = 31.831 A0.2 A = 9549 Hz
100 Hz = 19.099 A0.5 A = 3820 Hz
120 Hz = 15.916 A1 A = 1910 Hz
400 Hz = 4.775 A2 A = 955 Hz
500 Hz = 3.820 A5 A = 382 Hz
1000 Hz = 1.910 A10 A = 191 Hz
2000 Hz = 0.955 A20 A = 95.5 Hz
5000 Hz = 0.382 A30 A = 63.7 Hz
10000 Hz = 0.191 A40 A = 47.7 Hz
Formula (inductor): I = V ÷ (2π f L). Assumes RMS, V = 120 V, L = 10 mH.
Hz ↔ Amps Conversion Table (Capacitor, V = 120 V RMS, C = 10 µF)
Hz to Amps Amps to Hz
50 Hz = 0.377 A0.1 A = 13.3 Hz
60 Hz = 0.452 A0.2 A = 26.5 Hz
100 Hz = 0.754 A0.5 A = 66.3 Hz
120 Hz = 0.905 A1 A = 133 Hz
400 Hz = 3.016 A2 A = 265 Hz
500 Hz = 3.770 A5 A = 663 Hz
1000 Hz = 7.540 A10 A = 1326 Hz
2000 Hz = 15.080 A15 A = 1989 Hz
5000 Hz = 37.699 A20 A = 2653 Hz
10000 Hz = 75.398 A30 A = 3979 Hz
Formula (capacitor): I = 2π f C V. Assumes RMS, V = 120 V, C = 10 µF.
Hz ↔ Amps Conversion Table (Inductor, V = 240 V RMS, L = 10 mH)
Hz to Amps Amps to Hz
50 Hz = 76.394 A1 A = 3820 Hz
60 Hz = 63.662 A2 A = 1910 Hz
100 Hz = 38.197 A5 A = 763.9 Hz
400 Hz = 9.549 A10 A = 382 Hz
1000 Hz = 3.820 A20 A = 191 Hz
Formula (inductor): I = V ÷ (2π f L). Assumes RMS, V = 240 V, L = 10 mH.

Hz To Amps Formulas

Frequency (Hz) relates to current (Amps) through reactance. The formula depends on the type of reactive component in the circuit.

Inductor: I = V / (2 * pi * f * L)

Capacitor: I = 2 * pi * f * C * V

General RLC circuit: I = V / Z, where Z = sqrt(R^2 + (X_L - X_C)^2)

Variables:

  • I = current in amperes (A, RMS)
  • V = voltage (V, RMS)
  • f = frequency in hertz (Hz)
  • L = inductance in henries (H)
  • C = capacitance in farads (F)
  • R = resistance in ohms
  • X_L = inductive reactance = 2 * pi * f * L
  • X_C = capacitive reactance = 1 / (2 * pi * f * C)

For a pure inductor with no resistance, current drops as frequency rises because inductive reactance (X_L) increases linearly with frequency. The opposite is true for capacitors: capacitive reactance (X_C) falls as frequency rises, so current increases.

How Frequency and Current Interact in AC Circuits

Hz and Amps measure fundamentally different things. Hertz counts the number of complete voltage/current cycles per second. Amperes measure the rate of charge flow. There is no fixed ratio between them. The relationship depends entirely on the impedance of the circuit, which changes with the components present.

In a purely resistive circuit (a heater, an incandescent bulb), changing the frequency from 50 Hz to 60 Hz has zero effect on current. Resistance does not depend on frequency. In a circuit with inductors or capacitors, though, impedance is frequency-dependent, so the same voltage at a different frequency produces a different current.

Inductive Loads

Motors, transformers, solenoids, and chokes are inductive. Their reactance is X_L = 2 * pi * f * L. Double the frequency and the reactance doubles, cutting the current in half (assuming the same applied voltage). This is why equipment rated for 60 Hz grids draws more current if connected to a 50 Hz supply at the same voltage. A motor with 100 mH winding inductance sees X_L of about 31.4 ohms at 50 Hz but 37.7 ohms at 60 Hz.

Capacitive Loads

Power-factor correction capacitor banks, filter capacitors, and coupling capacitors are capacitive. Their reactance is X_C = 1 / (2 * pi * f * C). As frequency rises, X_C drops and current rises. A 10 uF capacitor at 120 V draws about 0.452 A at 60 Hz but 0.377 A at 50 Hz.

50 Hz vs 60 Hz Power Grids

Most of the world uses one of two standard AC frequencies. North America, parts of South America, South Korea, Saudi Arabia, and the Philippines use 60 Hz. Europe, most of Africa, Asia, and Australia use 50 Hz. Japan is split: eastern Japan (Tokyo, Yokohama) runs 50 Hz while western Japan (Osaka, Nagoya) runs 60 Hz, a legacy of importing different generators in the 1890s.

For purely resistive loads, the grid frequency does not matter. For reactive loads, the 20% frequency difference between 50 Hz and 60 Hz causes meaningful changes in current draw. A transformer core designed for 60 Hz will saturate at 50 Hz if the voltage is not reduced proportionally, drawing excess magnetizing current. Variable frequency drives (VFDs) exploit this relationship deliberately, controlling motor speed by adjusting the output frequency and voltage together.

Common Component Values and Their Currents

Knowing typical inductance and capacitance values for real components helps put the formulas in context. All values below assume 120 V RMS at 60 Hz unless noted.

  • Small AC motor (washing machine): winding inductance around 50 to 200 mH, drawing roughly 1 to 6 A depending on load and resistance.
  • Fluorescent lamp ballast: inductance around 0.5 to 2 H, limiting current to 0.3 to 0.5 A at line frequency.
  • Power-factor correction capacitor (residential): 5 to 25 uF, drawing 0.2 to 1.1 A of reactive current at 60 Hz / 120 V.
  • AC coupling capacitor (audio amplifier): 1 to 10 uF, passes milliamp-level signal currents at audio frequencies (20 Hz to 20 kHz).
  • Transformer primary (small appliance): inductance 1 to 10 H, magnetizing current well under 1 A at 60 Hz.

Worked Example

A 10 mH inductor is connected to a 120 V RMS, 60 Hz supply. Find the RMS current.

Step 1: Calculate inductive reactance. X_L = 2 * pi * 60 * 0.010 = 3.7699 ohms.

Step 2: Calculate current. I = 120 / 3.7699 = 31.831 A.

This matches the 60 Hz row in the inductor table above. In practice, real inductors also have DC winding resistance (often 0.5 to 5 ohms), which would reduce the actual current somewhat.

Skin Effect at High Frequencies

At frequencies above a few kHz, current concentrates near the surface of a conductor rather than flowing uniformly through its cross-section. This is called the skin effect. It increases the effective resistance of the conductor and reduces the current below what the simple reactance formula predicts. The skin depth in copper is about 9.3 mm at 50 Hz, 2.1 mm at 1 kHz, and 0.66 mm at 10 kHz. For power-frequency calculations (50 or 60 Hz), skin effect is usually negligible in conductors smaller than about 2 cm diameter. For high-frequency applications (switched-mode power supplies, RF circuits), it must be accounted for, and engineers use litz wire or hollow conductors to mitigate the losses.

Resonance

When an inductor and capacitor are in series, there is one specific frequency where X_L exactly equals X_C. At this resonant frequency, the two reactances cancel and the impedance drops to just the resistance R. Current reaches its maximum value of V / R, which can be many times higher than the current at other frequencies. The resonant frequency is f_r = 1 / (2 * pi * sqrt(L * C)). Series LC resonance is used in radio tuning circuits, bandpass filters, and can also cause dangerous overcurrents in power systems if a capacitor bank resonates with transformer inductance at a harmonic frequency.