Calculate average jump force from mass, jump height, and push distance, with results shown in newtons or pounds-force using metric or imperial units.
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Jump-Force Formula
F = m*g*(1 + h / d)
- F = average jump force or landing force
- m = mass
- g = acceleration due to gravity, 9.81 m/s²
- h = jump height
- d = push distance or landing deceleration distance
This formula gives the average force, not the peak force. It assumes the push or landing force is applied evenly over distance d. A shorter push or landing distance produces a higher force.
Useful Tables
The force is often easier to read as a multiple of body weight.
| Height ÷ Distance | Average Force | Meaning |
|---|---|---|
| 0.5 | 1.5 × body weight | Low force |
| 1 | 2 × body weight | Moderate force |
| 2 | 3 × body weight | High force |
| 5 | 6 × body weight | Very high force |
| Quantity | Conversion Used |
|---|---|
| Mass | 1 lb = 0.453592 kg |
| Distance | 1 ft = 0.3048 m |
| Distance | 1 in = 0.0254 m |
| Force | 1 lbf = 4.44822 N |
Quick Example
If your mass is 70 kg, jump height is 0.5 m, and push distance is 0.25 m:
F = 70*9.81*(1 + 0.5 / 0.25) = 2060.10 N
The average force is about 2060 N, or 3 times body weight.
