kWh to Amps Calculator

Convert kWh to amps from energy, voltage and run time for AC or DC circuits, or convert kW to amps directly, with amp-hours and real power shown.

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Calculator Functions

Function	What it does	What it requires
Current from energy and time	Finds the steady current in amps that uses a given amount of energy over a given run time	Requires the energy (Wh, kWh, MWh or GWh), the voltage and the run time
Current from power (kW to amps)	Converts real power in kW to current in amps, with no run time involved	Requires the real power (W, kW or MW) and the voltage
Energy from current and time	Finds the kWh used by a load that draws a steady current for a given time	Requires the current, the voltage and the run time
Voltage from energy and time	Finds the voltage at which a given current delivers a given amount of energy in a given time	Requires the energy, the current and the run time
Run time from energy and current	Finds how many hours a steady current takes to use a given amount of energy	Requires the energy, the voltage and the current

Every function also asks for the electrical system: AC single phase, DC or AC balanced three phase. The two AC choices add a true power factor, which is 1 unless changed. Run time can be entered in hours, minutes or seconds. Each result with a run time also shows the real power in kW and the charge in amp-hours.

kWh to Amps Formulas

A kilowatt-hour is one kilowatt sustained for one hour [2], so E ÷ t is the average power in kW. Multiplying by 1,000 gives watts, and dividing by the voltage terms gives amps. The three-phase form matches the U.S. Department of Energy equation for three-phase power, kW = V × I × PF × √3 ÷ 1,000 [1].

Current from energy and time

This is the main formula. 10 kWh used over 5 hours on a 240 V single-phase supply at a power factor of 1 is 1,000 × 10 ÷ (240 × 5) = 8.33 A. The same energy and time on a 400 V three-phase supply at a power factor of 0.85 is 1,000 × 10 ÷ (1.732 × 400 × 0.85 × 5) = 3.40 A.

Current from power (kW to amps)

P is the real power in kW. Power is already a rate, so no run time is needed: 7.2 kW at 240 V single phase and a power factor of 1 draws 30 A. The result also shows the apparent power in kVA, which is F × V × I ÷ 1,000.

Energy from current and time

This is the main formula solved for energy. A 15 A load on a 120 V single-phase circuit at a power factor of 1 uses 120 × 15 × 4 ÷ 1,000 = 7.2 kWh in 4 hours.

Voltage from energy and time

The main formula solved for voltage. 2.4 kWh delivered by 10 A in 2 hours on a single-phase or DC supply at a power factor of 1 means 120 V.

Run time from energy and current

The main formula solved for time. A 20 A load at 240 V single phase and a power factor of 1 takes 1,000 × 12 ÷ (240 × 20) = 2.5 hours to use 12 kWh.

kWh to amp-hours

Amp-hours measure charge, which is current multiplied by hours. For a DC battery the run time cancels out, so 1.2 kWh at 12 V is 100 Ah however fast it is drawn. The calculator lists this figure as Charge (amp-hours) under each result that has a run time.

How to Convert kWh to Amps

kWh measures energy and amps measure a rate of flow, so the conversion needs two more facts: the voltage and how long the energy was used over. Divide the kWh by the hours to get average kW, multiply by 1,000 to get watts, then divide by the volts. For AC, also divide by the power factor, and for three phase by √3. Over exactly 1 hour, kWh and average kW are the same number, so 1 kWh in 1 hour at 240 V is 4.167 A.

kWh in 1 hour	Amps at 120 V	Amps at 220 V	Amps at 230 V	Amps at 240 V
0.5	4.167	2.273	2.174	2.083
1	8.333	4.545	4.348	4.167
2	16.667	9.091	8.696	8.333
3	25	13.636	13.043	12.5
5	41.667	22.727	21.739	20.833
7.5	62.5	34.091	32.609	31.25
10	83.333	45.455	43.478	41.667
15	125	68.182	65.217	62.5
20	166.667	90.909	86.957	83.333
50	416.667	227.273	217.391	208.333

The table is for single-phase AC at a power factor of 1, or DC, with the energy used evenly over 1 hour. For energy spread over a longer period, divide the amps by the number of hours: 10 kWh over 24 hours at 240 V is 41.667 ÷ 24 = 1.736 A.

Limits of This Estimate

• The result is the average current of a steady load. An energy total cannot show peak current, motor inrush or how the load varied during the period.
• It is not an electrical installation design. Breaker, cable and equipment ratings need the actual load measurements and a qualified designer.
• The three-phase option assumes a balanced load, with line-to-line voltage and the same current in each line [1].
• A power factor of 1 suits heaters and other resistive loads. Motors and electronic loads draw more current for the same kWh, so use their measured power factor.

Sources