Select the empirical irrigation estimate or a rapid-closure Joukowsky calculation. Their inputs, assumptions and results differ; neither is a pipe safety or pressure-rating assessment.

Estimates only; not a pipe rating or safety assessment. Irrigation mode uses an empirical water formula. Joukowsky mode assumes rapid closure, a liquid-filled thin-wall elastic pipe and restraint factor 1. Presets are editable numerical examples, not verified design properties.

Surge Pressure Formula

The following idealized relationships estimate positive water-hammer pressure rise. The Joukowsky modes implement the rapid-closure equation. The separate irrigation mode uses the Hunter handbook estimate ฮ”P(psi) = 0.07 V(ft/s)L(ft)/t(s), not the slow-closure equation shown below.

ฮ” P = ฯ a ฮ” V, & tc โ‰ค (2L) / (a)\ (2ฯ L ฮ” V) / (tc), & tc > (2L) / (a)
  • Where ฮ”P is the surge pressure rise (Pa, psi, etc.)
  • ฯ is the fluid mass density (kg/mยณ)
  • a is the pressure wave speed (m/s)
  • ฮ”V is the change in flow velocity (m/s)
  • L is the pipe length (m)
  • tc is the valve closure time (s)

To estimate surge pressure rise, determine the wave travel time (2L/a). If the closure time is less than or equal to 2L/a (rapid closure), use the Joukowsky equation ฮ”P = ฯaฮ”V. If the closure is slower than 2L/a, an idealized slow-closure approximation reduces the peak rise roughly in proportion to (2L/a)/tc. This approximation is not calculated by the Joukowsky modes, and actual valve characteristics, pipe supports, entrained gas and reflections can change a transient. The widgetโ€™s elastic wave-speed formula assumes thin walls and a restraint factor of 1; its editable presets are numerical examples that need property verification.

How to Calculate Surge Pressure?

The following example problem outlines how to calculate the Surge Pressure rise.

Example Problem #1:

  1. First, determine the fluid density. In this example, the density is 1000 kg/mยณ (water).
  2. Next, determine the wave speed. For this example, assume a = 1200 m/s.
  3. Determine the pipe length and closure time. Let L = 300 m and tc = 0.2 s, so 2L/a = 2(300)/1200 = 0.5 s. Since tc โ‰ค 2L/a, treat this as rapid closure.
  4. Determine the change in velocity. If the flow drops from v1 = 1.5 m/s to v2 = 0 m/s, then ฮ”V = 1.5 m/s.
  5. Finally, calculate the surge pressure rise using ฮ”P = ฯaฮ”V.

ฮ”P = ฯ * a * ฮ”V

Inserting the values from above and solving the equation: 

ฮ”P = 1000 * 1200 * 1.5 = 1,800,000 Pa = 1.80 MPa โ‰ˆ 261 psi

FAQ

What is Surge Pressure?

Surge Pressure, often referred to as water hammer, is a pressure change that occurs in a piping system when there is a sudden change in the flow velocity of the fluid within the pipes. This can happen due to the rapid closing or opening of valves, or the sudden start or stop of a pump.

Why is it important to calculate Surge Pressure?

Calculating Surge Pressure is crucial for the design and operation of piping systems to ensure their safety and reliability. High Surge Pressures can cause damage to pipes, valves, and other components, potentially leading to system failure, leaks, or even hazardous accidents.

Can Surge Pressure be mitigated or controlled?

Yes, Surge Pressure can be mitigated or controlled through various methods. These include the installation of surge tanks, air chambers, or valves specifically designed to relieve pressure. Additionally, gradual changes in flow velocity and careful operational practices can help reduce the risk of surge pressure spikes.