Select mechanical shaft power, shaft speed, or shaft torque to solve for, then enter the other two values in W, kW, HP, RPM, rad/s, N-m, or lb-ft with step-by-step results.

Use mechanical power at the alternator shaft and shaft speed, not engine RPM. If starting with electrical output, first divide it by the alternator efficiency as a fraction. This tool uses nonnegative magnitudes.

HP means mechanical horsepower, approximated as 745.7 W. Electrical output power excludes conversion losses.

Alternator Torque Formula

The alternator torque calculation is based on the relationship between mechanical power, rotational speed, and torque. The calculator converts all inputs to base units first: watts for power, RPM for speed, and newton-meters for torque.

T = (P × 60) / (RPM × 2 × pi)
  • T = alternator torque in newton-meters, N-m
  • P = mechanical shaft power in watts, W
  • RPM = alternator speed in revolutions per minute
  • pi = 3.14159265

To calculate power instead of torque, the calculator rearranges the same relationship:

P = T × RPM × 2 × pi / 60

To calculate speed instead of torque, the calculator uses:

RPM = (P × 60) / (T × 2 × pi)
  • Torque mode: enter power and speed to find the shaft torque required to drive the alternator.
  • Power mode: enter torque and speed to find the mechanical power being transferred.
  • Speed mode: enter power and torque to find the alternator speed needed for that power level.

The calculator also supports unit conversions. Power can be entered in W, kW, or HP. Speed can be entered in RPM or rad/s. Torque can be entered in N-m or lb-ft.

Common Alternator Unit Conversions

These conversions are useful when checking the result or comparing it with equipment ratings.

Quantity Conversion Used by calculator
Power 1 kW = 1000 W Yes
Power 1 HP = 745.7 W Yes
Speed 1 rad/s ≈ 9.5493 RPM Yes
Torque 1 lbf-ft ≈ 1.355817948 N-m Yes
Torque 1 N-m ≈ 0.737562 lbf-ft Yes

Torque Examples at Selected Mechanical Power and Speed Values

Power Speed Approx. Torque
1 kW 1500 RPM 6.37 N-m
2 kW 1800 RPM 10.61 N-m
5 kW 3000 RPM 15.92 N-m
10 kW 3600 RPM 26.53 N-m

Example Calculations

Example 1: Calculate alternator torque

The mechanical input at the alternator shaft is 5 kW at 3000 RPM. Find the shaft torque.

T = (P × 60) / (RPM × 2 × pi)
T = (5000 × 60) / (3000 × 2 × pi)
T = 15.9155 N - m

The required alternator torque is about 15.92 N-m.

Example 2: Calculate alternator power

You have 20 N-m of torque at 1800 RPM. Find the power.

P = T × RPM × 2 × pi / 60
P = 20 × 1800 × 2 × pi / 60
P = 3769.91 W

The mechanical shaft power is about 3769.91 W, or 3.77 kW.

FAQ

Does this calculate electrical output torque or shaft torque?

This calculation gives the mechanical shaft torque associated with the entered power and speed. If you enter electrical output power, the result does not include alternator losses unless you adjust the power for efficiency. For example, if an alternator is 80% efficient and delivers 4 kW electrically, the required mechanical input power is 4 kW / 0.80 = 5 kW.

Why does torque decrease when RPM increases for the same power?

Power depends on both torque and rotational speed. For a fixed power value, a higher RPM means the same work is being delivered over more revolutions per minute, so less torque is needed per revolution. A lower RPM requires more torque to produce the same power.

Can I use horsepower instead of watts?

Yes. Select HP in the power unit dropdown. The calculator converts horsepower to watts using 1 HP = 745.7 W, performs the calculation, and displays solved power in watts with kW and HP equivalents.