Enter either the peak voltage or the average (rectified) voltage into the calculator to determine the other value.
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Average (Rectified) Voltage Formula
The following formula is used to calculate the average (rectified) voltage for a sine wave.
V_{avg,rect} = \frac{2}{\pi}V_p \approx 0.637\,V_pVariables:
- Where Vavg,rect is the average (rectified) voltage (volts)
- Vp is the peak voltage (volts)
To calculate the average (rectified) voltage, multiply the peak voltage by 0.637 (≈ 2/π).
This formula calculates the average (mean/DC) value of a full-wave-rectified sinusoidal voltage waveform (equivalently, the average of the absolute value of a sine wave). Note: a pure sinusoidal voltage centered around 0 V has an average of 0 V when averaged over a full cycle.
How to Calculate Average (Rectified) Voltage?
The following two example problems outline the steps and information needed in order to calculate the Average (Rectified) Voltage.
Example Problem #1:
- First, determine the peak voltage (volts) of the sine wave. In this example, the peak voltage is measured to be 50.
- Finally, calculate the average (rectified) voltage using the formula above:
Vavg,rect = Vp * 0.637
Inserting the values from above into the equation yields:
Vavg,rect = 50 * 0.637 = 31.85 (volts)
Example Problem #2:
Using the same process as the first example, define the variables outlined by the formula. In this case, these values are:
Peak voltage (volts) = 100
Entering these values into the formula or calculator above gives us:
Vavg,rect = Vp * 0.637 = 63.7 (volts)
