Select Boltzmann ratio, energy difference, or temperature to solve from the other two values, with unit conversions. This model assumes thermal equilibrium, equal statistical weights, and positive absolute temperature.

Compare two states at thermal equilibrium with equal statistical weights. Energy is per particle; temperature must be above absolute zero.

Eโ‚‚ โˆ’ Eโ‚, per particle. Negative values are allowed. Not energy per mole.

Must be greater than 0 K (โˆ’273.15 ยฐC or โˆ’459.67 ยฐF).


Related Calculators

Boltzmann Ratio Formula

For equal statistical weights at thermal equilibrium, the Boltzmann ratio gives the relative population of two energy states at a positive absolute temperature. The calculator uses the energy difference between the states, temperature, and the Boltzmann constant.

Nโ‚‚ / Nโ‚ = eโฝ - ฮ”E / (k ร— T))
ฮ”E = - k ร— T ร— ln(Nโ‚‚ / Nโ‚)
T = - ฮ”E / (k ร— ln(Nโ‚‚ / Nโ‚))
  • Nโ‚‚/Nโ‚ = Boltzmann ratio, the population of state 2 divided by the population of state 1
  • ฮ”E = energy difference between the two states, usually Eโ‚‚ โˆ’ Eโ‚
  • T = absolute temperature in kelvin
  • k = Boltzmann constant, 1.380649 ร— 10-23 J/K
  • e = Eulerโ€™s number
  • ln = natural logarithm

Select the value to solve, then enter the two visible inputs:

  • Boltzmann ratio: enter ฮ”E and T to find Nโ‚‚/Nโ‚.
  • Energy difference: enter T and Nโ‚‚/Nโ‚ to find ฮ”E.
  • Temperature: enter ฮ”E and Nโ‚‚/Nโ‚ to find T.

Energy is converted internally to joules, and temperature is converted internally to kelvin before the formula is applied. The ratio must be greater than zero because the natural logarithm of zero or a negative number is undefined. A ratio of 1 does not determine a unique finite temperature: with equal energies any positive temperature fits, and with unequal energies no finite temperature fits.

Energy and Temperature Reference Values

These tables can help you check whether your inputs are in the right scale.

Quantity Conversion to base unit Used by formula as
1 eV 1.602176634 ร— 10-19 J Energy per particle
1 kJ 1000 J Energy in joules
1 kcal 4184 J Energy in joules
0 ยฐC 273.15 K Absolute temperature
32 ยฐF 273.15 K Absolute temperature

Boltzmann ratio Nโ‚‚/Nโ‚ Meaning when ฮ”E = Eโ‚‚ โˆ’ Eโ‚
Greater than 1 State 2 is more populated than state 1. This usually means ฮ”E is negative.
Equal to 1 The two states have equal populations. This occurs when ฮ”E = 0.
Between 0 and 1 State 2 is less populated than state 1. This is typical when state 2 is higher in energy.
Very close to 0 State 2 has a much smaller population than state 1.

Example Calculations

Example 1: Find the Boltzmann ratio

Suppose the energy difference is 1.00 eV and the temperature is 300 K.

Nโ‚‚ / Nโ‚ = eโฝ - ฮ”E / (k ร— T))

Convert 1.00 eV to joules:

ฮ”E = 1.602176634 ร— 10โป19 J

Substitute the values:

Nโ‚‚ / Nโ‚ = eโฝ - (1.602176634 ร— 10โป19) / (1.380649 ร— 10โป23 ร— 300))

The result is approximately:

Nโ‚‚ / Nโ‚ = 1.59 ร— 10โป17

Example 2: Find the energy difference

Suppose the Boltzmann ratio is 0.01 and the temperature is 298.15 K.

ฮ”E = - k ร— T ร— ln(Nโ‚‚ / Nโ‚)

Substitute the values:

ฮ”E = - (1.380649 ร— 10โป23) ร— (298.15) ร— ln(0.01)

The result is approximately:

ฮ”E = 1.896 ร— 10โป20 J = 0.118 eV

FAQ

Why does temperature need to be in kelvin?

The Boltzmann equation uses absolute temperature. Celsius and Fahrenheit are relative scales, so they must be converted to kelvin before the calculation. This calculator requires temperature above 0 K. Zero would put zero in the denominator; negative absolute temperatures are outside its model.

Can the Boltzmann ratio be negative?

No. The Boltzmann ratio is a population ratio, so it must be positive. A ratio less than 1 means the second state is less populated than the first. A ratio greater than 1 means the second state is more populated than the first.

What if my energy is in kJ/mol?

The formula used here is written with the Boltzmann constant, so ฮ”E is treated as energy per particle. If your energy is molar, such as kJ/mol, convert it to energy per particle before using this form, or use the molar gas constant version of the equation.