Calculate projectile energy in foot-pounds and joules from weight and velocity, or solve for required velocity or projectile weight using grains, grams, fps, or metric units.

Calculate kinetic energy at the entered speed and measurement point.

Enter the mass of the projectile, excluding its case or propellant.

Use speed at the measurement point; zero gives zero kinetic energy.

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Foot-Pounds of Energy Formula

The calculator uses the standard kinetic energy equation, rewritten so you can plug in projectile weight in grains and velocity in feet per second directly.

KE = (m × v²) / 450,436.67979
  • KE = kinetic energy in foot-pounds (ft-lb)
  • m = projectile weight in grains (gr)
  • v = projectile velocity in feet per second (ft/s)
  • 450,436.67979 ≈ unit conversion divisor (2 × 7000 gr/lb × 32.17404856 ft/s²). The calculator uses SI mass and speed with the exact defined unit factors.

The equivalent divisor is approximately 450,436.67979 for grains and feet per second; 450,436 is a rounded convention. Energy scales linearly with weight but with the square of velocity, so doubling velocity quadruples energy. The figure is a muzzle or point-of-measurement value only. It does not account for drag, drop, or terminal performance.

The calculator converts mass to kilograms and speed to meters per second, computes E = ½mv² in joules, and converts the result using 1 ft·lbf = 1.3558179483314004 J.

The three modes use the same formula in different ways:

  • Energy mode: solves KE directly from weight and velocity.
  • Speed mode: solves v = √(2E/m) from mass and energy. Zero energy gives zero speed for a positive mass.
  • Mass mode: solves m = 2E/v² from positive speed and positive energy. Zero speed and zero energy do not determine a unique mass.

Reference Values

These are illustrative mass and speed inputs with kinetic energies rounded to the nearest whole foot-pound. They are not specifications for particular commercial loads. Actual measured speed varies with equipment and conditions; the broad classes in the second table are descriptive examples rather than performance thresholds.

Cartridge / Projectile Weight (gr) Velocity (ft/s) Energy (ft-lb)
.177 air pellet7.91,00018
.22 LR401,200128
Hunting arrow40028070
9mm Luger1241,150364
.45 ACP230850369
.357 Magnum1251,450583
.223 Remington553,2401,282
.308 Winchester1502,8002,611
.300 Win Mag1802,9603,501
Energy Range (ft-lb) Typical Class
Under 20Low-power airguns, light target pellets
20 – 80Magnum airguns, bows, light arrows
80 – 300Rimfire, heavy arrows, light handguns
300 – 800Common centerfire handgun loads
800 – 3,500Centerfire rifle loads
Over 3,500Magnum rifle and large dangerous-game loads

Worked Examples and Common Questions

Example 1: 9mm 124 gr at 1,150 ft/s.
KE ≈ (124 × 1,150²) / 450,436.67979 = 364.07 ft·lbf, or 493.61 J. Rounded to a whole foot-pound, this is 364 ft·lbf.

Example 2: .308 150 gr at 2,800 ft/s.
KE ≈ (150 × 2,800²) / 450,436.67979 = 2,610.80 ft·lbf, which rounds to 2,611 ft·lbf.

Example 3: Reverse solve. For 500 ft·lbf and a 230 gr projectile, speed ≈ sqrt(500 × 450,436.67979 / 230) = 989.55 ft/s, or 990 ft/s rounded to a whole unit.

Why grains and ft/s? The divisor approximately 450,436.67979 combines the mass, speed and energy unit factors. If m is mass in pounds and v is speed in ft/s, the equivalent divisor is 2 × 32.17404856. Grains and pounds here measure mass; the foot-pound energy unit is foot times pound-force.

Does foot-pounds measure stopping power? No. Foot-pounds is kinetic energy at the muzzle or chronograph point. Terminal effect depends on bullet construction, expansion, penetration, and shot placement. Use ft-lb to compare loads, not to predict wound performance.

How accurate is the result? This is the classical kinetic-energy model for ordinary nonrelativistic speeds. Display precision does not establish measurement accuracy. For a 150 gr projectile at 2,800 ft/s, increasing speed by 50 ft/s raises energy by about 94.08 ft·lbf; decreasing it by 50 ft/s lowers energy by about 92.41 ft·lbf.

Converting to joules. Multiply ft·lbf by 1.3558179483314004. Thus exactly 364 ft·lbf is about 493.52 J; the unrounded 124 gr example gives 493.61 J. The calculator shows both energy units.

Why does velocity matter more than weight? Energy scales with v². A 10% velocity increase raises energy about 21%. A 10% weight increase raises energy only 10%. That is why high-velocity rifle rounds outpace heavy but slow handgun rounds in ft-lb even with much lighter projectiles.