Calculate the missing plasmid molar ratio value from plasmid and insert copy numbers and molecular weights using a 1:1 mass basis.
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Plasmid Molar Ratio Formula
The following relationship comes from the mass–mole connection (mass = moles × molar mass). On a 1:1 mass basis (total plasmid mass equals total insert mass), the copy (mole) counts satisfy: P · Wp = I · Wi. Rearranging gives the missing variable formula below.
P = (I * Wi) / Wp
Variables:
- P is the number of copies of plasmid
- I is the number of copies of insert
- Wp is the molecular weight (molar mass) of plasmid
- Wi is the molecular weight (molar mass) of insert
To calculate the number of copies of plasmid (on a 1:1 mass basis), multiply the number of copies of insert by the molecular weight of the insert, then divide by the molecular weight of the plasmid.
What is a Plasmid Molar Ratio?
In cloning and ligation workflows, a “molar ratio” typically refers to the ratio of insert molecules to vector (plasmid) molecules (for example, 3:1 insert:vector). This page’s calculator uses molecular weights (molar masses) to relate insert and plasmid copy counts on a 1:1 mass basis, which can help you understand what molar ratio you get when you start from equal masses. For double-stranded DNA, a common approximation is ~660 g/mol per base pair to estimate molecular weight from length.
How to Calculate Plasmid Molar Ratio?
The following steps outline how to use the relationship above (1:1 mass basis) to calculate the missing value.
- First, determine the number of copies of plasmid (P) or leave it blank to solve for it.
- Next, determine the molecular weight (molar mass) of the insert (Wi).
- Next, determine the number of copies of insert (I).
- Next, determine the molecular weight (molar mass) of the plasmid (Wp).
- Finally, calculate the missing variable using the formula provided above (derived from P · Wp = I · Wi).
- After inserting the values and calculating the result, check your answer with the calculator above.
Example Problem :
Use the following variables as an example problem to test your knowledge.
Number of copies of insert (I) = 10
Molecular weight of plasmid (Wp) = 1,980,000 g/mol
Molecular weight of insert (Wi) = 330,000 g/mol
Using P = (I · Wi) / Wp: P = (10 × 330,000) / 1,980,000 ≈ 1.67 (i.e., on an equal-mass basis, this corresponds to an insert:plasmid molar ratio of about 6:1).