Enter the engine speed, injector pulse width and desired end angle into the calculator to determine the injector timing.
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Injector End Angle Formula
The following formula is used to calculate the injector end angle for a given injector start angle, injection duration, and engine speed.
\theta_e = \theta_s + D \, S \times 0.006
Variables:
- θe is the injector end angle in degrees (crank degrees)
- θs is the injector start angle in degrees (crank degrees)
- D is the injection duration in milliseconds
- S is the engine speed in RPM
To calculate the injector end angle, convert the injection duration into crankshaft degrees using Δθ = D × S × 0.006 (since 0.006 = 360/60000), then add that angle change to the injector start angle. If you are working on a 4-stroke 0–720° reference, you may wrap the final angle into your preferred range as needed.
What is an Injector End Angle?
The injector end angle is a critical parameter in internal combustion engines, particularly in fuel injection systems. It represents the crankshaft angle at which the fuel injection process ends. Accurate calculation of the injector end angle helps ensure appropriate fuel delivery timing, combustion efficiency, and engine performance. This parameter is used for tuning and calibrating the engine control unit (ECU) to achieve desired performance and emissions standards.
How to Calculate Injector End Angle?
The following steps outline how to calculate the Injector End Angle.
- First, determine the injector start angle (θs).
- Next, determine the injection duration (D).
- Next, determine the engine speed (S).
- Finally, calculate the injector end angle using the formula (θe = θs + D × S × 0.006), with D in milliseconds and S in RPM.
- After inserting the values and calculating the result, check your answer with the calculator above.
Example Problem :
Use the following variables as an example problem to test your knowledge.
Injector Start Angle (θs) = 30 degrees
Injection Duration (D) = 2 ms
Engine Speed (S) = 3000 RPM
Injector End Angle (θe) = 30 + (2 × 3000 × 0.006) = 66 degrees