Calculate vibration g force, frequency, displacement, or time from any three values with unit conversions for Hz, m, s, and g, and calculation steps.
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Vibration G Force Formula
Vibration g-force expresses sinusoidal acceleration as a multiple of standard gravity. For a vibrating system with displacement amplitude D, frequency f, and time t, the motion can be modeled from displacement to acceleration and then converted into g’s.
x(t) = D\sin(2\pi f t)
a(t) = -(2\pi f)^2D\sin(2\pi f t)
GF(t) = \frac{|a(t)|}{g_0} = \frac{(2\pi f)^2D\left|\sin(2\pi f t)\right|}{9.80665}Where:
- GF(t) = instantaneous vibration g-force
- D = displacement amplitude in meters
- f = frequency in hertz
- t = time in seconds
- 9.80665 = standard gravity in m/s2
The calculator reports the magnitude of the acceleration, so the displayed result is non-negative. If you need the directional sign of the acceleration, use the signed acceleration expression instead of the magnitude form.
Peak Vibration G Force
If you want the maximum acceleration reached during one full cycle, use the peak form. This occurs when the sine term reaches its maximum magnitude.
GF_{peak} = \frac{(2\pi f)^2D}{9.80665}This version is especially useful for shaker testing, machinery vibration checks, design limits, and quick comparisons between different amplitudes and frequencies.
Useful Rearrangements
If you know the peak g-force and need to solve for displacement amplitude or frequency, these forms are helpful:
D = \frac{GF_{peak}\cdot 9.80665}{(2\pi f)^2}f = \frac{1}{2\pi}\sqrt{\frac{GF_{peak}\cdot 9.80665}{D}}D = \frac{X_{pp}}{2}Use the last relation when your measurement is peak-to-peak displacement rather than amplitude. Entering peak-to-peak travel as amplitude will overstate the calculated g-force.
How to Calculate Vibration G Force
- Convert frequency to hertz, displacement amplitude to meters, and time to seconds.
- If your motion is given as peak-to-peak displacement, divide by 2 to get amplitude.
- Determine the phase of the motion from frequency and time.
- Compute acceleration from the sinusoidal relation.
- Divide acceleration by standard gravity to express the result in g.
\theta = 2\pi f t
At the start of a cycle, the instantaneous g-force is zero. At one-quarter of a cycle, the instantaneous g-force reaches its peak magnitude.
Example
Suppose a vibration has a frequency of 400 Hz, a displacement amplitude of 1.25 mm, and a time equal to one-quarter of a cycle. At that instant, the sine term equals 1, so the instantaneous g-force is also the peak g-force.
D = 1.25\text{ mm} = 0.00125\text{ m}t = \frac{1}{4\cdot 400} = 0.000625\text{ s}GF(t) = \frac{(2\pi\cdot 400)^2\cdot 0.00125\cdot \sin(2\pi\cdot 400\cdot 0.000625)}{9.80665} \approx 805.13The vibration acceleration is approximately 805.13 g.
Quick Interpretation
| Change | Effect on Vibration G Force |
|---|---|
| Double the displacement amplitude | The g-force doubles |
| Double the frequency | The g-force increases by four times |
| Measure at the start of a cycle | The instantaneous g-force is zero |
| Measure at one-quarter of a cycle | The instantaneous g-force reaches peak magnitude |
Input Notes That Prevent Errors
- Amplitude is not total travel. If a system moves 2 mm peak-to-peak, the amplitude is 1 mm.
- Frequency has the strongest influence. Because acceleration scales with the square of frequency, even modest frequency increases can produce much larger g values.
- Time only matters for instantaneous results. If you only need the highest acceleration in a cycle, use the peak formula.
- Magnitude removes direction. The positive and negative halves of the cycle have opposite acceleration directions but the same magnitude.
- Unit consistency matters. Most unrealistic outputs come from mixing inches, millimeters, hertz, or time units without converting properly.
Where This Calculation Is Used
- Rotating machinery and imbalance analysis
- Shaker table and sinusoidal vibration testing
- Electronics, sensors, and PCB durability checks
- Automotive and aerospace vibration environments
- Mount, isolator, and fixture design reviews
- Comparing allowable vibration limits against test conditions
Assumptions and Limits
This calculator is intended for sinusoidal vibration. It is most accurate when the motion can be represented by a single frequency and a single displacement amplitude.
- It does not model random vibration spectra.
- It does not replace shock or impact calculations.
- It assumes the reported displacement is the amplitude for the same axis being evaluated.
- Inverse solutions can have multiple valid times because sinusoidal motion repeats every cycle.
Frequently Asked Questions
What is the difference between acceleration in m/s2 and acceleration in g?
They describe the same physical acceleration on different scales. Expressing acceleration in g simply normalizes it by standard gravity.
GF = \frac{a}{9.80665}Why can a very small displacement create a very large g-force?
Because vibration acceleration grows with the square of frequency. High-frequency motion can create large acceleration even when the actual displacement is tiny.
When should I use peak g-force instead of instantaneous g-force?
Use peak g-force when you want the maximum acceleration reached during a cycle. Use instantaneous g-force when the exact time or phase of motion matters.
Is vibration g-force the same as shock g-force?
No. Vibration g-force is typically tied to continuous periodic motion, while shock g-force describes a short-duration impact or pulse. The analysis methods and assumptions are different.
What is the most common input mistake?
The most common mistake is entering peak-to-peak displacement as amplitude. If your displacement measurement is peak-to-peak, divide it by 2 before using the formula or calculator.
