Calculate water cooling wattage from coolant flow rate and temperature rise, or find the flow or temperature change needed for a heat load in W or BTU/h.
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Water Cooling Wattage Formula
The steady-flow sensible-heat model is Qฬ = แน cp |ฮT| = ฯ Vฬ cp |ฮT|. With volumetric flow F in L/min, water density 1000 kg/mยณ and cp = 4182 J/(kgยทK), the coefficient is 69.7 W per (L/minยทK).
- Qฬ = sensible heat-transfer rate magnitude, in watts
- F = water flow rate, in liters per minute
- ฮT = temperature difference between inlet and outlet water, in ยฐC
- 69.7 = coefficient for this constant-property water approximation
The water preset uses 4182 J/(kgยทK) and 1000 kg/mยณ as approximations. PG30 and PG50 preserve the prior 1030/3700 and 1060/3400 density/specific-heat pairs as illustrative scenarios; their temperature and mass/volume concentration basis were unspecified, so they are not verified mixture data. For a real coolant, enter manufacturer properties at the stated concentration basis and operating or mean temperature. A 1ยฐF difference equals 5/9 K; absolute Fahrenheit temperatures also require the 32-degree offset.
Water Cooling Unit Conversions
These are the conversions used before and after the main calculation.
| Quantity | Conversion | Use |
|---|---|---|
| Power | 1 W = 3.41214 BTU/hr | Convert watts to BTU/hr |
| Power | 1 BTU/hr = 0.293071 W | Convert BTU/hr to watts |
| Flow rate | 1 US GPM = 3.785411784 L/min | Convert gallons per minute to liters per minute |
| Temperature difference | 1ยฐF difference = 5/9ยฐC difference | Convert a Fahrenheit temperature rise or drop |
Cooling Wattage per 1 L/min of Water Flow
Quick checks for the same 1000 kg/mยณ, 4182 J/(kgยทK) water approximation. Values scale linearly with flow and temperature difference while properties remain constant.
| Water ฮT | Cooling at 1 L/min | Cooling at 1 L/min |
|---|---|---|
| 1ยฐC | 69.7 W | 237.8 BtuIT/h |
| 2ยฐC | 139.4 W | 475.7 BtuIT/h |
| 5ยฐC | 348.5 W | 1,189.1 BtuIT/h |
| 10ยฐC | 697.0 W | 2,378.3 BtuIT/h |
Example Check
If water flows at 3 L/min and rises by 4ยฐC, the cooling wattage is:
At constant properties, a larger temperature difference or flow increases the sensible heat carried by the stream. Mass-flow modes use Qฬ = แน cp |Tenter โ Tleave| and can reverse for mass flow. Cooling uses Tleave = Tenter โ Qฬ/(แน cp); heating uses the plus sign, and the entering-temperature mode reverses it. The model assumes steady single-phase liquid flow with suitable mean properties. It excludes latent heat, pump heat, fouling and heat-exchanger approach; it does not establish radiator capacity. Check freezing/boiling limits and actual equipment performance separately.
