Enter the system voltage and the total equivalent impedance (or resistance in a DC circuit) of the fault path into the calculator to estimate the prospective fault current.
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Fault Current Formula
The following formula (Ohm’s law) can be used to estimate prospective fault current when you know the voltage and the total equivalent impedance seen at the fault point (for DC circuits, impedance is just resistance).
FC = V/Z
- Where FC is the fault current (amps)
- V is the applicable voltage at the fault (volts)
- Z is the total equivalent impedance of the fault path (ohms)
To calculate the fault current, divide the applicable voltage by the magnitude of the total fault-path impedance. In AC power systems, the voltage used (line-to-line vs. line-to-neutral) depends on the type of fault being analyzed (e.g., three-phase vs. line-to-ground), and the impedance typically includes both resistance and reactance.
Fault Current Definition
Fault current is the current that flows when an electrical fault (such as a short circuit) occurs. The available (or prospective) fault current at a point is the maximum current the system can deliver into a fault at that location under stated conditions, and it depends on the source and network impedance and the type of fault.
During a bolted fault the fault-path impedance can be very low, which can make the current very large. In most real power systems, however, the fault current is primarily limited by the total Thevenin/source impedance of the supply (transformers, generators, and conductors), not just the fault’s own resistance.
How to calculate fault current?
Example Problem #1.
First, determine the voltage of the system. For this example, we will use 120 volts as the voltage.
Next, determine the total equivalent impedance (or resistance in a DC circuit) seen by the source at the fault point. For this problem, we will say the impedance magnitude is 0.25 ohms.
Finally, use Ohm's Law to calculate the fault current.
I = V/Z
= 120/0.25
= 480 amps.
Example Problem #2.
In this next example, we will take a look to see how much a smaller impedance affects the current.
Again, we will use the same voltage as above, 120 V.
In this problem, the impedance magnitude is now reduced to only 0.05 ohms.
Using the formula as in example 1:
I = V/Z
= 120/0.05
= 2,400 amps.
This is 5 times the current of example 1.
