Calculate adiabatic compression or expansion temperature, pressure, volume ratios, work, and energy from initial gas conditions and γ.
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Adiabatic Compression Temperature Formula
The calculator uses reversible adiabatic ideal-gas relationships. Use absolute temperature and absolute pressure values. Temperatures entered in °C or °F are converted to kelvin for the calculation, then converted back for display.
T_2 = T_1\left(\frac{P_2}{P_1}\right)^{(\gamma-1)/\gamma}T_2 = T_1\left(\frac{V_1}{V_2}\right)^{\gamma-1}\frac{P_2}{P_1}=\left(\frac{V_1}{V_2}\right)^\gammaP_1V_1^\gamma=P_2V_2^\gamma
T_1V_1^{\gamma-1}=T_2V_2^{\gamma-1}Q=0
C_v=\frac{R}{\gamma-1}\Delta U=nC_v(T_2-T_1)
W_{by\ gas}=\frac{P_1V_1-P_2V_2}{\gamma-1}- T₁ = initial absolute temperature
- T₂ = final absolute temperature
- P₁ = initial absolute pressure
- P₂ = final absolute pressure
- V₁ = initial volume
- V₂ = final volume
- γ = heat capacity ratio, equal to Cₚ/Cᵥ
- R = ideal gas constant, 8.314462618 J/(mol·K)
- n = amount of gas in moles
- Q = heat transfer, zero for an adiabatic process
- ΔU = internal energy change
- W by gas = work done by the gas
Compression Temp: calculates the final temperature after adiabatic compression from an outlet pressure, pressure ratio, or volume compression ratio.
Expansion Temp: uses the same temperature relation, but the pressure ratio is usually less than 1, so the gas cools during expansion.
Advanced Solver: fills missing state values using the pressure, volume, and temperature adiabatic relations when enough state data is supplied.
Work & Energy: solves the final state and calculates Cᵥ, Cₚ, internal energy change, work done by the gas, and heat transfer.
Common Gamma Values and Result Interpretation
Use a custom γ value if you have a gas-specific value at the temperature range of your process.
| Gas | Typical γ | Notes |
|---|---|---|
| Air, nitrogen, oxygen | 1.400 | Common default for room-temperature diatomic gases |
| Helium, argon | 1.667 | Monatomic gases, larger temperature change for the same pressure ratio |
| Carbon dioxide | 1.289 | Lower γ, smaller temperature change for the same pressure ratio |
| Steam | 1.330 | Approximate ideal-gas value, not suitable near saturation |
| Condition | Pressure ratio P₂/P₁ | Temperature result | Energy result |
|---|---|---|---|
| Compression | Greater than 1 | T₂ is greater than T₁ | ΔU is positive, work by gas is negative |
| Expansion | Less than 1 | T₂ is less than T₁ | ΔU is negative, work by gas is positive |
| No pressure change | Equal to 1 | T₂ equals T₁ | No ideal adiabatic work or internal energy change |
Examples
Example 1: Air compressed from 1 atm to 10 atm
You have air with γ = 1.4, T₁ = 300 K, P₁ = 1 atm, and P₂ = 10 atm.
T_2=300\left(\frac{10}{1}\right)^{(1.4-1)/1.4}The exponent is 0.285714, so:
T₂ = 579.21 K
The compression ratio is:
\frac{V_1}{V_2}=10^{1/1.4}=5.1795Example 2: Air expanding from 10 bar to 1 bar
You have air with γ = 1.4, T₁ = 600 K, P₁ = 10 bar, and P₂ = 1 bar.
T_2=600\left(\frac{1}{10}\right)^{(1.4-1)/1.4}T₂ = 310.73 K
The expansion ratio is:
\frac{V_2}{V_1}=\left(\frac{10}{1}\right)^{1/1.4}=5.1795FAQ
Do you need absolute pressure or gauge pressure?
Use absolute pressure. If you have gauge pressure, add atmospheric pressure before entering it. For example, 100 psi gauge is about 114.7 psi absolute at normal atmospheric pressure.
Why does temperature rise during adiabatic compression?
In adiabatic compression, no heat is transferred out of the gas. Work is done on the gas, increasing its internal energy. For an ideal gas, higher internal energy means higher temperature.
When is this calculation not accurate?
It becomes less accurate when the gas is not close to ideal, when heat transfer is significant, when friction and losses are important, or when γ changes strongly with temperature. Real compressors and turbines often need efficiency corrections in addition to the ideal adiabatic result.